SUM UNTIL THE GIVEN NUMBER BECOME SINGLE DIGIT

 PROGRAM TO DO FOLLOWING OPERATION:

EXPLANATION:

N=5347=5+3+4+7

ITS SUM=19

AGAIN SUM OF 1+9 IS 10

AGAIN SUM OF 1+0=1

NOW 1 IS A SINGLE DIGIT DIGIT SO ITS PRINT 1 AS OUTPUT

I/P:5347

O/P:1

SOLUTION:

import java.util.*;

public class SumUntilSingleDigit {

    public static void main(String args[])

    {

        Scanner sc=new Scanner(System.in);

        int iNum=sc.nextInt();

        int sum=10;

        int temp=iNum;

        int b=0;

        while(sum>=10)

        {

           sum=0;

            while(iNum>0)

            {

                b=iNum%10;

                sum+=b;

               // System.out.println(sum);

                iNum/=10;

            }

           iNum=sum;

           

        

           

        }

        System.out.print(sum);

    }

    

}